<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:georss='http://www.georss.org/georss' xmlns:gd='http://schemas.google.com/g/2005' xmlns:thr='http://purl.org/syndication/thread/1.0'><id>tag:blogger.com,1999:blog-3214485946806701894</id><updated>2011-11-27T19:05:59.090-05:00</updated><title type='text'>Math Teasers</title><subtitle type='html'>Collection of math puzzles, teasers, and word games. (Hints and solutions sometimes appear as comments.)</subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default?max-results=100'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>26</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>100</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-9151625811423349096</id><published>2010-03-19T13:37:00.000-04:00</published><updated>2010-03-24T18:44:04.327-04:00</updated><title type='text'>Inverse of a Matrix</title><content type='html'>The inverse of a square non-singular matrix A is the matrix of cofactors of A divided by the determinant of A. A cofactor of an element of&amp;nbsp;A is the determinant of the matrix which results from crossing out the row and column of A that contains the element,&amp;nbsp;and which is then multiplied by -1 to the power of i+j, where i is the row and j is the column. Non-singular means that the determinant of A doesn't equal zero.&lt;br /&gt;&lt;br /&gt;What is the inverse of the matrix A given below? Some of the cofactors of A and the determinant of A have been computed for you.&lt;br /&gt;&lt;div class="separator" style="clear: both; text-align: center;"&gt;&lt;a href="http://2.bp.blogspot.com/_ANbW-099TZ4/S6PFWBY0UxI/AAAAAAAAAPE/Pwanq1i9YEk/s1600-h/Inverse.png" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"&gt;&lt;img border="0" height="400" src="http://2.bp.blogspot.com/_ANbW-099TZ4/S6PFWBY0UxI/AAAAAAAAAPE/Pwanq1i9YEk/s400/Inverse.png" vt="true" width="352" /&gt;&lt;/a&gt;&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-9151625811423349096?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/9151625811423349096/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/03/inverse-of-matrix_19.html#comment-form' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/9151625811423349096'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/9151625811423349096'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/03/inverse-of-matrix_19.html' title='Inverse of a Matrix'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://2.bp.blogspot.com/_ANbW-099TZ4/S6PFWBY0UxI/AAAAAAAAAPE/Pwanq1i9YEk/s72-c/Inverse.png' height='72' width='72'/><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-4040785572978318399</id><published>2010-03-18T09:08:00.000-04:00</published><updated>2010-03-19T14:17:56.636-04:00</updated><title type='text'>Trace of a Matrix</title><content type='html'>The trace of a matrix is the sum of the diagonal elements of the matrix.&lt;br /&gt;&lt;br /&gt;Let U be the 3x3 unit matrix:&lt;br /&gt;&lt;br /&gt;1 0 0&lt;br /&gt;0 1 0&lt;br /&gt;0 0 1&lt;br /&gt;&lt;br /&gt;The trace of U is Tr(U) = 3.&lt;br /&gt;&lt;br /&gt;Does Tr(5U) = 15 ?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-4040785572978318399?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/4040785572978318399/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/03/trace-of-matrix.html#comment-form' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/4040785572978318399'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/4040785572978318399'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/03/trace-of-matrix.html' title='Trace of a Matrix'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-7556675860850154861</id><published>2010-03-17T10:20:00.000-04:00</published><updated>2010-03-17T10:32:42.042-04:00</updated><title type='text'>Determinant of a Matrix</title><content type='html'>Let U be the 3x3 unit matrix:&lt;br /&gt;&lt;br /&gt;1 0 0&lt;br /&gt;0 1 0&lt;br /&gt;0 0 1&lt;br /&gt;&lt;br /&gt;The determinant of U is Det(U) = 1.&lt;br /&gt;&lt;br /&gt;Does Det(5U) = 5 ?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-7556675860850154861?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/7556675860850154861/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/03/determinant-of-matrix.html#comment-form' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/7556675860850154861'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/7556675860850154861'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/03/determinant-of-matrix.html' title='Determinant of a Matrix'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-2331042408203841197</id><published>2010-03-17T09:58:00.000-04:00</published><updated>2010-03-17T10:30:46.315-04:00</updated><title type='text'>Square Root</title><content type='html'>Suppose M and m are positive numbers,&amp;nbsp;with M&amp;nbsp;greater than m. Does the square root of the square of&amp;nbsp; (m - M):&lt;br /&gt;&lt;br /&gt;sqrt((m - M)(m - M))&lt;br /&gt;&lt;br /&gt;equal &lt;br /&gt;&lt;br /&gt;(m - M) ?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-2331042408203841197?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/2331042408203841197/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/03/square-root.html#comment-form' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/2331042408203841197'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/2331042408203841197'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/03/square-root.html' title='Square Root'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-80098085287969941</id><published>2010-03-11T19:04:00.000-05:00</published><updated>2010-03-13T10:58:14.769-05:00</updated><title type='text'>Euclid's Proof of Pythagorean Theorem</title><content type='html'>Let the yellow triangle be a right triangle. Show that the sum of the areas of the blue and green squares equals the area of the&amp;nbsp;red square. Verify the following:&lt;br /&gt;&lt;br /&gt;&lt;ul&gt;&lt;li&gt;Notice that triangles ABD and CDF are congruent (identical)&lt;/li&gt;&lt;li&gt;Area of triangle CDF = one-half the area of the blue square&lt;/li&gt;&lt;li&gt;Area of triangle ABD = one-half the area of rectangle AGED&lt;/li&gt;&lt;li&gt;Therefore, area of the blue square = area of rectangle AGED&lt;/li&gt;&lt;li&gt;Surmise that a similar analysis will show that the area of the green square = area of rectangle GHFE&lt;/li&gt;&lt;li&gt;And therefore, that the sum of the areas of the blue and green squares equals the area of the red square&lt;/li&gt;&lt;/ul&gt;Since the area of each square = the square of&amp;nbsp;the corresponding&amp;nbsp;side of the yellow triangle, the theorem of Pythagoras is proved.&lt;br /&gt;&lt;div class="separator" style="clear: both; text-align: center;"&gt;&lt;a href="http://3.bp.blogspot.com/_ANbW-099TZ4/S5meY3l8L7I/AAAAAAAAAOc/CQmhkZzsabI/s1600-h/euler.png" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"&gt;&lt;img border="0" height="400" src="http://3.bp.blogspot.com/_ANbW-099TZ4/S5meY3l8L7I/AAAAAAAAAOc/CQmhkZzsabI/s400/euler.png" vt="true" width="308" /&gt;&lt;/a&gt;&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-80098085287969941?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/80098085287969941/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/03/eulers-proof-of-pythagorean-theorem.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/80098085287969941'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/80098085287969941'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/03/eulers-proof-of-pythagorean-theorem.html' title='Euclid&apos;s Proof of Pythagorean Theorem'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_ANbW-099TZ4/S5meY3l8L7I/AAAAAAAAAOc/CQmhkZzsabI/s72-c/euler.png' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-2814735824362233491</id><published>2010-03-02T12:59:00.001-05:00</published><updated>2010-03-11T22:34:57.349-05:00</updated><title type='text'>Intersecting Circles: Longest Line</title><content type='html'>Show that line BAC is longest when lines BD and CD pass through the centers of the circles. Also show that line BAC is perpendicular to line AD when this happens. &lt;br /&gt;&lt;br /&gt;&lt;ul&gt;&lt;li&gt;Notice that angles B and C don't change as line BAC is rotated about point A. (Investigate some of the posts below with the large yellow circles.) &lt;/li&gt;&lt;li&gt;This means that all triangles BDC are similar (have the same shape, but differ in size). So all sides of triangle BDC must maximize at the same time.&lt;/li&gt;&lt;li&gt;Note also that the line between the centers of the circles is perpendicular to line AD, because the two circles are symmetric about the horizontal line drawn through their centers.&lt;/li&gt;&lt;/ul&gt;&lt;br /&gt;&lt;div class="separator" style="clear: both; text-align: center;"&gt;&lt;a href="http://2.bp.blogspot.com/_ANbW-099TZ4/S41W64EvRTI/AAAAAAAAAN8/FPuwvSY4LMg/s1600-h/2circles.png" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"&gt;&lt;img border="0" height="308" kt="true" src="http://2.bp.blogspot.com/_ANbW-099TZ4/S41W64EvRTI/AAAAAAAAAN8/FPuwvSY4LMg/s400/2circles.png" width="400" /&gt;&lt;/a&gt;&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-2814735824362233491?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/2814735824362233491/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/03/intersecting-circles-longest-line.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/2814735824362233491'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/2814735824362233491'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/03/intersecting-circles-longest-line.html' title='Intersecting Circles: Longest Line'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://2.bp.blogspot.com/_ANbW-099TZ4/S41W64EvRTI/AAAAAAAAAN8/FPuwvSY4LMg/s72-c/2circles.png' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-7263666876436024837</id><published>2010-01-28T22:04:00.000-05:00</published><updated>2010-02-14T14:17:47.358-05:00</updated><title type='text'>Circles in Circles</title><content type='html'>If the radius of the small circle is 1, and the radius of the large circle is 3, what is the radius of the still larger circle that has&amp;nbsp;as arcs those curves which are tangent to the small circle?&lt;br /&gt;&lt;br /&gt;&lt;div class="separator" style="clear: both; text-align: center;"&gt;&lt;a href="http://4.bp.blogspot.com/_ANbW-099TZ4/S2JQKq8xJ0I/AAAAAAAAABU/PJivNqM95zo/s1600-h/pic7.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"&gt;&lt;img border="0" height="320" kt="true" src="http://4.bp.blogspot.com/_ANbW-099TZ4/S2JQKq8xJ0I/AAAAAAAAABU/PJivNqM95zo/s320/pic7.jpg" width="314" /&gt;&lt;/a&gt;&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-7263666876436024837?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/7263666876436024837/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/01/circles-in-circles.html#comment-form' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/7263666876436024837'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/7263666876436024837'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/01/circles-in-circles.html' title='Circles in Circles'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://4.bp.blogspot.com/_ANbW-099TZ4/S2JQKq8xJ0I/AAAAAAAAABU/PJivNqM95zo/s72-c/pic7.jpg' height='72' width='72'/><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-4102939778476928627</id><published>2010-01-28T21:23:00.000-05:00</published><updated>2010-03-13T09:08:32.483-05:00</updated><title type='text'>Intersecting Circles</title><content type='html'>Two circles of radius 1 intersect in such a way that the perimeter of each circle passes through the center of the other circle. Show that the area of intersection (the GREEN area) has area: 2*pi/3 - sqrt(3)/2.&lt;br /&gt;&lt;br /&gt;&lt;ul&gt;&lt;li&gt;Draw&amp;nbsp;an equilateral triangle with vertices at the centers of the circles and at the point of intersection of the two circles at the top of the figure&lt;/li&gt;&lt;li&gt;Calculate the area of the triangle: 1/2 * base * height = 1/2 *&amp;nbsp;sqrt(3)/2&lt;/li&gt;&lt;li&gt;Area of corresponding sector of the circle = pi/6&lt;/li&gt;&lt;li&gt;Difference between areas = pi/6 - sqrt(3)/4&lt;/li&gt;&lt;li&gt;Add this difference to the&amp;nbsp;area of the sector of the circle. The result is: pi/3 - sqrt(3)/4&lt;/li&gt;&lt;li&gt;Multiply by 2 to include the lower half of the green area&lt;/li&gt;&lt;/ul&gt;&lt;br /&gt;&lt;div class="separator" style="clear: both; text-align: center;"&gt;&lt;a href="http://3.bp.blogspot.com/_ANbW-099TZ4/S2JGhmtouCI/AAAAAAAAABM/lHx8Nr87drk/s1600-h/pic6.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"&gt;&lt;img border="0" height="241" kt="true" src="http://3.bp.blogspot.com/_ANbW-099TZ4/S2JGhmtouCI/AAAAAAAAABM/lHx8Nr87drk/s320/pic6.jpg" width="320" /&gt;&lt;/a&gt;&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-4102939778476928627?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/4102939778476928627/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/01/intersecting-circles.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/4102939778476928627'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/4102939778476928627'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/01/intersecting-circles.html' title='Intersecting Circles'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_ANbW-099TZ4/S2JGhmtouCI/AAAAAAAAABM/lHx8Nr87drk/s72-c/pic6.jpg' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-2646801647964276919</id><published>2010-01-25T15:02:00.000-05:00</published><updated>2010-02-13T22:16:12.200-05:00</updated><title type='text'>Show: Angle B = 2 * Angle A</title><content type='html'>Show that angle B at the center of the circle is twice as large as angle A.&lt;br /&gt;&lt;br /&gt;&lt;div class="separator" style="clear: both; text-align: center;"&gt;&lt;a href="http://1.bp.blogspot.com/_ANbW-099TZ4/S3dozvzxx8I/AAAAAAAAANU/2ORp7lrKytU/s1600-h/pic6.png" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"&gt;&lt;img border="0" ct="true" height="313" src="http://1.bp.blogspot.com/_ANbW-099TZ4/S3dozvzxx8I/AAAAAAAAANU/2ORp7lrKytU/s320/pic6.png" width="320" /&gt;&lt;/a&gt;&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-2646801647964276919?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/2646801647964276919/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/02/show-angle-b-2-angle.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/2646801647964276919'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/2646801647964276919'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/02/show-angle-b-2-angle.html' title='Show: Angle B = 2 * Angle A'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://1.bp.blogspot.com/_ANbW-099TZ4/S3dozvzxx8I/AAAAAAAAANU/2ORp7lrKytU/s72-c/pic6.png' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-1639853435523993573</id><published>2010-01-25T15:01:00.000-05:00</published><updated>2010-03-13T11:08:12.581-05:00</updated><title type='text'>Show: Angle F = 2 * Angle E</title><content type='html'>Show that angle F at the center of the circle is twice as large as angle E. (Hint: Use the result of the above post: Draw two figures like the figure in the above post, but in the same circle, and then add or subtract angles.)&lt;br /&gt;&lt;br /&gt;&lt;div class="separator" style="clear: both; text-align: center;"&gt;&lt;a href="http://1.bp.blogspot.com/_ANbW-099TZ4/S3hEK20P4zI/AAAAAAAAANc/nVHQOKGMN3E/s1600-h/pic5.png" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"&gt;&lt;img border="0" ct="true" height="317" src="http://1.bp.blogspot.com/_ANbW-099TZ4/S3hEK20P4zI/AAAAAAAAANc/nVHQOKGMN3E/s320/pic5.png" width="320" /&gt;&lt;/a&gt;&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-1639853435523993573?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/1639853435523993573/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/01/angles-in-circles-special-properties.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/1639853435523993573'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/1639853435523993573'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/01/angles-in-circles-special-properties.html' title='Show: Angle F = 2 * Angle E'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://1.bp.blogspot.com/_ANbW-099TZ4/S3hEK20P4zI/AAAAAAAAANc/nVHQOKGMN3E/s72-c/pic5.png' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-5717341806297146052</id><published>2010-01-25T14:48:00.000-05:00</published><updated>2010-03-12T09:28:19.323-05:00</updated><title type='text'>Inscribed Quadrilateral</title><content type='html'>Prove: A + C = B + D = 180 degrees. (Hint:&amp;nbsp;Draw a line from B to the center of the circle, and another line from the center of the circle to D. Then use the result of the above post. The sum of the central angles must equal 360 degrees. This will yield A + C = 180 degrees. Repeat for angles B and D.)&lt;br /&gt;&lt;br /&gt;&lt;div class="separator" style="clear: both; text-align: center;"&gt;&lt;a href="http://3.bp.blogspot.com/_ANbW-099TZ4/S3hK3b0fQtI/AAAAAAAAANk/lHbaOkH7RRY/s1600-h/pic4.png" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"&gt;&lt;img border="0" ct="true" height="319" src="http://3.bp.blogspot.com/_ANbW-099TZ4/S3hK3b0fQtI/AAAAAAAAANk/lHbaOkH7RRY/s320/pic4.png" width="320" /&gt;&lt;/a&gt;&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-5717341806297146052?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/5717341806297146052/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/01/inscribed-quadrilateral.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/5717341806297146052'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/5717341806297146052'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/01/inscribed-quadrilateral.html' title='Inscribed Quadrilateral'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_ANbW-099TZ4/S3hK3b0fQtI/AAAAAAAAANk/lHbaOkH7RRY/s72-c/pic4.png' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-156287987238272079</id><published>2010-01-24T15:27:00.000-05:00</published><updated>2010-03-12T10:34:44.285-05:00</updated><title type='text'>Japanese Temple Problem from 1844</title><content type='html'>Show that the area of the&amp;nbsp;red&amp;nbsp;triangle = the area of the&amp;nbsp;red square. (Hint:&amp;nbsp;Check out the figure &lt;a href="http://labbysway.com/temple.png" target="_blank"&gt;here&lt;/a&gt;. Note that the area of the red triangle = area of trapezoid minus the area of the two triangles within the trapezoid. The area of the trapezoid = (a+b)*(1/2)*(2a+2b).)&lt;br /&gt;&lt;br /&gt;&lt;div class="separator" style="clear: both; text-align: center;"&gt;&lt;a href="http://2.bp.blogspot.com/_ANbW-099TZ4/S13KXwIXX7I/AAAAAAAAAA0/fr1FOPCyiak/s1600-h/pic3.png" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"&gt;&lt;img border="0" height="245" mt="true" src="http://2.bp.blogspot.com/_ANbW-099TZ4/S13KXwIXX7I/AAAAAAAAAA0/fr1FOPCyiak/s320/pic3.png" width="320" /&gt;&lt;/a&gt;&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-156287987238272079?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/156287987238272079/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/01/show-area-of-purple-triangle-area-of.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/156287987238272079'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/156287987238272079'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/01/show-area-of-purple-triangle-area-of.html' title='Japanese Temple Problem from 1844'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://2.bp.blogspot.com/_ANbW-099TZ4/S13KXwIXX7I/AAAAAAAAAA0/fr1FOPCyiak/s72-c/pic3.png' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-312995790676537224</id><published>2010-01-24T13:20:00.001-05:00</published><updated>2011-01-31T09:21:26.162-05:00</updated><title type='text'>Diameter of Circle inscribed in Trapezoid = ?</title><content type='html'>&lt;div dir="ltr" style="text-align: left;" trbidi="on"&gt;Find the diameter of the circle&amp;nbsp;inscribed in the trapezoid. (Hint: The two tangents from a given point to a given circle have the same length. The length of the slanted sides of the trapezoid should therefore be immediately obvious.)&lt;br /&gt;&lt;div class="separator" style="clear: both; text-align: center;"&gt;&lt;a href="http://3.bp.blogspot.com/_ANbW-099TZ4/S1yPGbN78cI/AAAAAAAAAAU/tZj6LR0PG04/s1600-h/pic2.png" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"&gt;&lt;img border="0" height="273" mt="true" src="http://3.bp.blogspot.com/_ANbW-099TZ4/S1yPGbN78cI/AAAAAAAAAAU/tZj6LR0PG04/s320/pic2.png" width="320" /&gt;&lt;/a&gt;&lt;/div&gt;&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-312995790676537224?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/312995790676537224/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/01/diameter-of-circle-inscribed-in.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/312995790676537224'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/312995790676537224'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/01/diameter-of-circle-inscribed-in.html' title='Diameter of Circle inscribed in Trapezoid = ?'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_ANbW-099TZ4/S1yPGbN78cI/AAAAAAAAAAU/tZj6LR0PG04/s72-c/pic2.png' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-7825031056946845705</id><published>2010-01-24T12:36:00.000-05:00</published><updated>2010-03-06T07:18:25.433-05:00</updated><title type='text'>Area of Triangle = A; Area of Ellipse = B = ?</title><content type='html'>Shown are&amp;nbsp;four&amp;nbsp;identical rectangles, as well as a triangle&amp;nbsp;with area A, and an ellipse with area B. What does area B equal in terms of area A? No pencil or paper is needed. (Hint: Area of an ellipse = pi*(semimajor axis)*(semiminor axis.))&lt;br /&gt;&lt;br /&gt;&lt;div class="separator" style="clear: both; text-align: center;"&gt;&lt;a href="http://2.bp.blogspot.com/_ANbW-099TZ4/S5BH6ZJSpUI/AAAAAAAAAOM/qHYHQviR74E/s1600-h/pic1.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"&gt;&lt;img border="0" height="400" kt="true" src="http://2.bp.blogspot.com/_ANbW-099TZ4/S5BH6ZJSpUI/AAAAAAAAAOM/qHYHQviR74E/s400/pic1.jpg" width="241" /&gt;&lt;/a&gt;&lt;/div&gt;&lt;br /&gt;&lt;div class="separator" style="clear: both; text-align: center;"&gt;&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-7825031056946845705?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/7825031056946845705/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/01/area-8-area-b-no-pencil-or-paper-is.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/7825031056946845705'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/7825031056946845705'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/01/area-8-area-b-no-pencil-or-paper-is.html' title='Area of Triangle = A; Area of Ellipse = B = ?'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://2.bp.blogspot.com/_ANbW-099TZ4/S5BH6ZJSpUI/AAAAAAAAAOM/qHYHQviR74E/s72-c/pic1.jpg' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-3950185657623894672</id><published>2010-01-20T16:00:00.001-05:00</published><updated>2010-01-20T16:00:50.289-05:00</updated><title type='text'>Odd Pair of Letters</title><content type='html'>Which is the odd pair of letters?&lt;br /&gt;BY, HS, EV, JR, GT&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-3950185657623894672?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/3950185657623894672/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/01/odd-pair-of-letters.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/3950185657623894672'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/3950185657623894672'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/01/odd-pair-of-letters.html' title='Odd Pair of Letters'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-7663817964946604035</id><published>2010-01-20T15:59:00.002-05:00</published><updated>2010-01-20T16:00:05.645-05:00</updated><title type='text'>Odd Word Out</title><content type='html'>Which word is the odd one out?&lt;br /&gt;BLITHERING CATHEDRAL WAREHOUSE&lt;br /&gt;PROMETHEAN STEPMOTHER&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-7663817964946604035?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/7663817964946604035/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/01/odd-word-out.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/7663817964946604035'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/7663817964946604035'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/01/odd-word-out.html' title='Odd Word Out'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-3703114232201103833</id><published>2010-01-20T15:59:00.001-05:00</published><updated>2010-01-20T15:59:40.224-05:00</updated><title type='text'>Rearrangement</title><content type='html'>Rearrange the letters in NEW DOOR to form one word.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-3703114232201103833?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/3703114232201103833/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/01/rearrangement.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/3703114232201103833'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/3703114232201103833'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/01/rearrangement.html' title='Rearrangement'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-1923269237408360247</id><published>2010-01-20T15:58:00.002-05:00</published><updated>2010-01-20T16:04:51.973-05:00</updated><title type='text'>Sequence 5</title><content type='html'>What number comes next in the sequence?&lt;br /&gt;1 11 21 1211 111221 ?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-1923269237408360247?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/1923269237408360247/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/01/sequence-6.html#comment-form' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/1923269237408360247'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/1923269237408360247'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/01/sequence-6.html' title='Sequence 5'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-1314023656238546002</id><published>2010-01-20T15:58:00.001-05:00</published><updated>2010-01-20T15:58:45.147-05:00</updated><title type='text'>Die Throws</title><content type='html'>With a standard six-sided die, how many throws are required on average before each of the six numbers has landed faceup?&lt;br /&gt;(a) 10 (b) 15 (c) 20 (d) 25&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-1314023656238546002?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/1314023656238546002/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/01/die-throws.html#comment-form' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/1314023656238546002'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/1314023656238546002'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/01/die-throws.html' title='Die Throws'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-89471608741149900</id><published>2010-01-20T15:57:00.002-05:00</published><updated>2010-01-20T15:58:13.358-05:00</updated><title type='text'>Moving Digits</title><content type='html'>Move one digit to a new position so that the equation below is&lt;br /&gt;correct. (Moving signs is not allowed.)&lt;br /&gt;62 – 63 = 1&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-89471608741149900?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/89471608741149900/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/01/moving-digits.html#comment-form' title='2 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/89471608741149900'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/89471608741149900'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/01/moving-digits.html' title='Moving Digits'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-4756369427828138806</id><published>2010-01-20T15:57:00.001-05:00</published><updated>2010-01-20T16:04:39.262-05:00</updated><title type='text'>Sequence 4</title><content type='html'>What is the next number in the sequence?&lt;br /&gt;1 4 7 12 23 42 ?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-4756369427828138806?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/4756369427828138806/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/01/sequence-5.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/4756369427828138806'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/4756369427828138806'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/01/sequence-5.html' title='Sequence 4'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-5919853655365198880</id><published>2010-01-20T15:56:00.000-05:00</published><updated>2010-01-20T16:04:20.730-05:00</updated><title type='text'>Sequence 3</title><content type='html'>What is the next number in the series?&lt;br /&gt;77 49 36 18 ?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-5919853655365198880?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/5919853655365198880/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/01/series-1.html#comment-form' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/5919853655365198880'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/5919853655365198880'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/01/series-1.html' title='Sequence 3'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-6861760371340353332</id><published>2010-01-20T15:55:00.002-05:00</published><updated>2010-01-20T15:56:43.716-05:00</updated><title type='text'>Passenger Seats</title><content type='html'>The cost of hiring a private rail carriage is shared equally by all the passengers. The carriage has seats for forty passengers and the total bill amounts to $70.37. How many passenger seats are not occupied?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-6861760371340353332?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/6861760371340353332/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/01/passenger-seats.html#comment-form' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/6861760371340353332'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/6861760371340353332'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/01/passenger-seats.html' title='Passenger Seats'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-5364565132856900971</id><published>2010-01-20T15:55:00.001-05:00</published><updated>2010-01-20T15:55:44.034-05:00</updated><title type='text'>Sequence 2</title><content type='html'>What number replaces the question mark?&lt;br /&gt;1 4 3 11 15 13 17 ?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-5364565132856900971?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/5364565132856900971/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/01/sequence-2.html#comment-form' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/5364565132856900971'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/5364565132856900971'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/01/sequence-2.html' title='Sequence 2'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-6321431138137104707</id><published>2010-01-20T15:53:00.000-05:00</published><updated>2010-01-20T15:55:10.424-05:00</updated><title type='text'>Sequence 1</title><content type='html'>What number comes next in the sequence?&lt;br /&gt;4 6 5 4 2 3 ?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-6321431138137104707?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/6321431138137104707/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/01/sequence-1.html#comment-form' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/6321431138137104707'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/6321431138137104707'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/01/sequence-1.html' title='Sequence 1'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3214485946806701894.post-4217582950014786131</id><published>2010-01-20T15:41:00.000-05:00</published><updated>2010-03-11T22:17:47.434-05:00</updated><title type='text'>Two Boats</title><content type='html'>Two boats travelling at a constant speed start moving at the same instant from opposite sides of the Hudson River, one going from New York City to Jersey City, and the other from Jersey City to New York City. They pass one another at a point 720 yards from the New York shore.&lt;br /&gt;&lt;br /&gt;After arriving at their respective destinations, each boat spends precisely 10 minutes at the opposite shore to change passengers before switching directions. On the return trip, the two boats meet at a point 400 yards from the Jersey shore.&lt;br /&gt;&lt;br /&gt;After&amp;nbsp;arriving at their respective destinations, each boat&amp;nbsp;again spends precisely 10 minutes at the opposite shore to change passengers before switching directions. How far from the New York shore will the two boats be when they meet for the third time?&lt;br /&gt;&lt;br /&gt;(Hint: Find the width of the river. When the two boats meet for the first time, they will have travelled a total distance of&amp;nbsp;one width of the river. How many widths will they have travelled by the time they meet the second time? (The answer is&amp;nbsp;NOT two widths.) By the time thet meet the third time? Do the 10 minutes even matter?)&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3214485946806701894-4217582950014786131?l=mathteasers.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathteasers.blogspot.com/feeds/4217582950014786131/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathteasers.blogspot.com/2010/01/two-boats-travelling-at-constant-speed.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/4217582950014786131'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3214485946806701894/posts/default/4217582950014786131'/><link rel='alternate' type='text/html' href='http://mathteasers.blogspot.com/2010/01/two-boats-travelling-at-constant-speed.html' title='Two Boats'/><author><name>jr</name><uri>http://www.blogger.com/profile/14411464441737826763</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry></feed>
